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valentinak56 [21]
4 years ago
7

Everything!!!!!!!!!!!!!!!im lost.

Mathematics
1 answer:
Aleks04 [339]4 years ago
6 0
Z5emus5n64a7yM Zau64n4b73YU6
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8 0
3 years ago
At what points on the graph of f(x)=2x^3-6x^2-27x is the slope of the tangent line -9?
Dmitriy789 [7]

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(-1, 19) and (3, -81)

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f(x) = 2x³ − 6x² − 27x

f'(x) = 6x² − 12x − 27

-9 = 6x² − 12x − 27

0 = 6x² − 12x − 18

0 = x² − 2x − 3

0 = (x + 1) (x − 3)

x = -1 or 3

f(-1) = 19

f(3) = -81

The points are (-1, 19) and (3, -81).

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