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marshall27 [118]
2 years ago
9

In which of the following do you expect the correlation coefficient to be negative?

Mathematics
1 answer:
gavmur [86]2 years ago
4 0

Answer: A????????????

Step-by-step explanation:

you need to show the following

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Which functions domain consists of all real numbers except -2?
Eddi Din [679]

Answer:

option (a) f(x)= 1/x+2

Step-by-step explanation:

(a) f(x) = 1/ x+2

To find the restriction for domain , we set the denominator =0  and solve for x

x+2 =0, so x=-2

When x=-2  then denominator becomes 0 that is undefined.

So, domain is all real numbers except -2

(b) f(x)= 2x

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

(c) f(x) = 2x-2

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

f(x) = 1/ sqrt(x+2)

if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined

x+2>0, x>-2

Hence domain is all real numbers that are greater than -2

8 0
3 years ago
The answer that is blue isn’t really the answer i chose
babunello [35]
I thought it was the one above it but I think you are right tho

4 0
2 years ago
.<br> 7-9p≥7 or 2p - 9&gt; 11
My name is Ann [436]

Answer:

2p-9>

Step-by-step explanation:

7 0
2 years ago
Prove that for all n in the naturals, n(n+1)(n+2) is divisible by 3
DerKrebs [107]
By induction:

It's true for n=1, since 1\cdot2\cdot3 clearly contains a factor of 3.

Suppose it's true for n=k, that k(k+1)(k+2) is divisible by 3. Then

(k+1)(k+2)(k+3)=\dfrac{k(k+1)(k+2)(k+3)}k=\dfrac{3m(k+3)}k

where m is an integer. This reduces to

\dfrac{3m(k+3)}k=3m+9\dfrac mk

and both terms are clearly multiples of 3. We know that \dfrac mk is an integer since we had set m=k(k+1)(k+2) previously, which implies m is a multiple of k. So the statement is true.
6 0
3 years ago
Evaluate each expression for the given values of the variable.<br><br> −4√ef -4ef, where e=7 and f=7
mina [271]
-4\sqrt{ef} -4ef
-4\sqrt{(7)(7)} -4(7)(7)
-4\sqrt{7^2} -196
-4(7) -196
-28-196
-224
6 0
3 years ago
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