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nexus9112 [7]
3 years ago
11

Can anyone help me plz?

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0
<h3>Answer: Third choice. \overline{AC} \perp \overline{BD}</h3>

==================================================

Explanation:

SAS stands for Side Angle Side. Note how the angle is between the two sides. To prove the triangles congruent with SAS, we need to know two sides and an angle between them.

We already see that BC = CD as shown by the tickmarks. Another pair of sides is AC = AC through the reflexive theorem.

The missing info is the angle measures of ACB and ACD. If we knew those angles were the same, then we could use SAS to prove triangle ACB is congruent to triangle ACD.

It turns out that the angles are congruent only when they are 90 degrees each, leading to AC being perpendicular to BD. We write this as \overline{AC} \perp \overline {BD}. The upside down T symbol meaning "perpendicular" or "the two segments form a right angle".

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There were 4 apple trees planted and 3 pecan trees. 2 peach trees for 3 pecan trees. If there 24 peach trees, how many apple tre
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➷ 4 : 3

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Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xey + yez + ze
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Answer: 6 / √26

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Given that f(x, y, z) = xe^y + ye^z + ze^x

so first we compute the gradient vector at (0, 0, 0)

Δf ( x, y, z ) = [ e^y + ze^x,  xe^y + e^z,  ye^z + e^x ]

Δf ( 0, 0, 0 ) = [ e⁰ + 0(e)⁰, 0(e)⁰ + e⁰, 0(e)⁰ + e⁰ ] = [ 1+0 , 0+1, 0+1 ] = [ 1, 1, 1 ]

Now we were also given that  V = < 4, 3, -1 >

so ║v║ = √ ( 4² + 3² + (-1)² )

║v║ = √ ( 16 + 9 + 1 )

║v║ = √ 26

It must be noted that "v"  is not a unit vector but since ║v║ = √ 26, the unit vector in the direction of "V" is ⊆ = ( V / ║v║)

so

⊆ =  ( V / ║v║) = [ 4/√26, 3/√26, -1/√26 ]

therefore by equation   D⊆f ( x, y, z ) = Δf ( x, y, z ) × ⊆

D⊆f ( x, y, z ) = Δf ( 0, 0, 0 ) × ⊆ = [ 1, 1, 1 ] × [ 4/√26, 3/√26, -1/√26 ]

= ( 1×4 + 1×3 -1×1 ) / √26

= (4 + 3 - 1) / √26

= 6 / √26

8 0
4 years ago
Need help as fast plz
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