Answer:
9/4<x≤4 or all real numbers
Step-by-step explanation:
I'm not sure what you are asking
Need more information. Can’t answer d=2 the answer would have to be “d”
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Trini took 74 photos
<em><u>Solution:</u></em>
Given that Trini took some photos
The number of photos she took is a two-digit number
Let the number in unit place be x and the number in tens place be y
Then the two digit number is yx
Given that sum of digits is 11
Therefore,
x + y = 11 ---- eqn 1
The tens digit is 3 more than the ones digit
Therefore, we frame a equation as,
y = 3 + x ---- eqn 2
<em><u>Solve eqn 1 and eqn 2 to get value of "x" and "y"</u></em>
Substitute eqn 2 in eqn 1
x + 3 + x = 11
2x + 3 = 11
2x = 11 - 3
2x = 8
x = 4
Substitute x = 4 in eqn 2
y = 3 + 4 = 7
Thus the two digit number is 74. Thus he took 74 photos
