A) Demand function
price (x) demand (D(x))
4 540
3.50 810
D - 540 810 - 540
----------- = -----------------
x - 4 3.50 - 4
D - 540
----------- = - 540
x - 4
D - 540 = - 540(x - 4)
D = -540x + 2160 + 540
D = 2700 - 540x
D(x) = 2700 - 540x
Revenue function, R(x)
R(x) = price * demand = x * D(x)
R(x) = x* (2700 - 540x) = 2700x - 540x^2
b) Profit, P(x)
profit = revenue - cost
P(x) = R(x) - 30
P(x) = [2700x - 540x^2] - 30
P(x) = 2700x - 540x^2 - 30
Largest possible profit => vertex of the parabola
vertex of 2700x - 540x^2 - 30
When you calculate the vertex you find x = 5 /2
=> P(x) = 3345
Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.
23 is a whole number 75 is the numerator and use 100 as the denominator since 75 is in the 100nths place.
Answer:
area of the floor = 540*840.
=453600 cm sq.
area of the marbal piece = 1/2 * 40* 30 = 600 cm sq.
now,
no. of marble piece reqd. = 453600 / 600 = 756 marbal piece.
hope it helps u.
The amount of profit the spirit club make on each shirt sold at the end of the year is = $2
<h3>Calculation of profit</h3>
The quantity of shirt bought by the club = $8 per shirt
At the end of the year they sold the shirts at discount of %25 each.
That is 25/100 × 8
= 200/100
= $2
Therefore, they made profit of $2 for each shirt they sold at the end of the year.
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Answer:
4 3=64
Step-by-step explanation:
