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guapka [62]
2 years ago
6

PLEASSSEEEE help me with all three and if they are CORRECT I will give you brainliest

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0

Answer:

1)

{x}^{2 \times3}  {y}^{5 \times 3}

{x}^{6}   {y}^{15}

2) 8+4=12

3) xy³÷x⁴y²=

{x}^{ -3}  {y}^{ - 1}

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Should be B the total numbers of boxes filled with reams
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Aleks [24]

Answer: 75

Step-by-step explanation:

Multiple all those numbers together and then divide by 3

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What is different about the normality requirement for a confidence interval estimate of sigma and the normality requirement for
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The normality requirement for a confidence interval estimate of sigma is (stricter) than the normality requirement for a confidence interval estimate of mu. Departures from normality have a (greater) effect on confidence interval estimates of sigma than on confidence interval estimates of mu. That is, a confidence interval estimate of sigma is (less)

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Answer: 212998.58

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2 years ago
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Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
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