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guapka [62]
3 years ago
6

PLEASSSEEEE help me with all three and if they are CORRECT I will give you brainliest

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

1)

{x}^{2 \times3}  {y}^{5 \times 3}

{x}^{6}   {y}^{15}

2) 8+4=12

3) xy³÷x⁴y²=

{x}^{ -3}  {y}^{ - 1}

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54:63 in simplest form
Bas_tet [7]

Answer:

I think it is 6/7

Step-by-step explanation:

I am really bad at explaining but I'm not completely sure

4 0
3 years ago
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What is the DOMAIN of this graph?
Ksenya-84 [330]

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Is yellow

Step-by-step explanation:

an open circle for "less than" or "greater than", and a closed circle for "less than or equal to"

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3 years ago
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andrew-mc [135]
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4 years ago
Solve sin (x)(sin(x)-1) =0
iogann1982 [59]

Answer:

x=n \pi or x=2\pi n+\frac{\pi}{2}

Step-by-step explanation:

The given trigonometric equation is;

\sin x(\sin x-1)=0

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\sin x=0 or \sin x-1=0

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6 0
4 years ago
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The coordinates of the vertices of △PQR are P(1, 4) , Q(2, 2) , and R(−2, 1) . The coordinates of the vertices of △P′Q′R′ are P′
butalik [34]

<u>ANSWER </u>

The correct answer is option B


<u>EXPLANATION</u>


When we analyse carefully we can see that PQR is mapped on to P'Q'R' by the rule

(x,y)\rightarrow (-x,y)


P(1,4)\rightarrow P'(-1,4)


Q(2,2)\rightarrow Q'(-2,2)


R(-2,1)\rightarrow R'(2,2)


That is to say the <em>x-coordinates</em> are <em>negated</em>. Hence y-axis is the mirror line.


Since reflection is a rigid motion, the two triangles are congruent. That means the two triangles PQR and P'Q'R' are equal in all respect.


See graph in attachment.

5 0
4 years ago
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