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3 years ago

What is the equation of the linear function written in slope-intercept form?

Mathematics

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$f(x)=mx+b$

m - slope

b - y-intercept, (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the graph we have two points A(-1, 2) and B(0, -1) → b = -1.

Calculate the slope:

$m=\dfrac{-1-2}{0-(-1)}=\dfrac{-3}{1}=-3$

Finally:

$f(x)=-3x-1$

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Can someone plz help me

Colt1911 [192]

Answer:

x is less than or equal to negative 14.

Step-by-step explanation:

so for now we should pretend that the greater than or equal to is an equal sign, and simplify the problem to get x alone on a side

remove 5 from each side

-x/3=1/3-5

-x/3=14/3

multiply both sides by 3

-x=14

x=-14

so we can now replace the equal sign with the equal or greater to, so x is less than or equal to -14

4 0

3 years ago

4 friends evenly divided up a n- slice pizza. One of the friends , Harris, ate 1 fewer slice than he received. How many slices o

LenKa [72]

4 friends evenly dividing up a n - slice pizza

So each one get $\frac{n}{4}$ slices of pizza.

For example, if n = 12 slice then each friend gets 12/4 = 3 pieces. If Harris ate one slice less then he ate $\frac{12}{4}-1$ =3 -1 = 2 pieces.

So the general expression for slices of pizza did Harris eat is

$\frac{n}{4}-1$

6 0

3 years ago

Read 2 more answers

PLEASE HELP, GOOD ANSWERS GET BRAINLIEST. +40 POINTS WRONG ANSWERS GET REPORTED

MA_775_DIABLO [31]

1. Ans:(A) 123

Given function: $f(x) = 8x^2 + 11x$
The derivative would be:
$\frac{d}{dx} f(x) = \frac{d}{dx}(8x^2 + 11x)$
=> $\frac{d}{dx} f(x) = \frac{d}{dx}(8x^2) + \frac{d}{dx}(11x)$
=> $\frac{d}{dx} f(x) = 2*8(x^{2-1}) + 11$
=> $\frac{d}{dx} f(x) = 16x + 11$

Now at x = 7:
$\frac{d}{dx} f(7) = 16(7) + 11$

=> $\frac{d}{dx} f(7) = 123$

2. Ans:(B) 3

Given function: $f(x) =3x + 8$
The derivative would be:
$\frac{d}{dx} f(x) = \frac{d}{dx}(3x + 8)$
=> $\frac{d}{dx} f(x) = \frac{d}{dx}(3x) + \frac{d}{dx}(8)$
=> $\frac{d}{dx} f(x) = 3*1 + 0$
=> $\frac{d}{dx} f(x) = 3$

Now at x = 4:
$\frac{d}{dx} f(4) = 3$ (as constant)

=>Ans: $\frac{d}{dx} f(4) =$ 3

3. Ans:(D) -5

Given function: $f(x) = \frac{5}{x}$
The derivative would be:
$\frac{d}{dx} f(x) = \frac{d}{dx}(\frac{5}{x})$
or
$\frac{d}{dx} f(x) = \frac{d}{dx}(5x^{-1})$
=> $\frac{d}{dx} f(x) = 5*(-1)*(x^{-1-1})$
=> $\frac{d}{dx} f(x) = -5x^{-2}$

Now at x = -1:
$\frac{d}{dx} f(-1) = -5(-1)^{-2}$

=> $\frac{d}{dx} f(-1) = -5 *\frac{1}{(-1)^{2}}$
=> Ans: $\frac{d}{dx} f(-1) = -5$

4. Ans:(C) 7 divided by 9

Given function: $f(x) = \frac{-7}{x}$
The derivative would be:
$\frac{d}{dx} f(x) = \frac{d}{dx}(\frac{-7}{x})$
or
$\frac{d}{dx} f(x) = \frac{d}{dx}(-7x^{-1})$
=> $\frac{d}{dx} f(x) = -7*(-1)*(x^{-1-1})$
=> $\frac{d}{dx} f(x) = 7x^{-2}$

Now at x = -3:
$\frac{d}{dx} f(-3) = 7(-3)^{-2}$

=> $\frac{d}{dx} f(-3) = 7 *\frac{1}{(-3)^{2}}$
=> Ans: $\frac{d}{dx} f(-3) = \frac{7}{9}$

5. Ans:(C) -8

Given function:
$f(x) = x^2 - 8$

Now if we apply limit:
$\lim_{x \to 0} f(x) = \lim_{x \to 0} (x^2 - 8)$

=> $\lim_{x \to 0} f(x) = (0)^2 - 8$
=> Ans: $\lim_{x \to 0} f(x) = - 8$

6. Ans:(C) 9

Given function:
$f(x) = x^2 + 3x - 1$

Now if we apply limit:
$\lim_{x \to 2} f(x) = \lim_{x \to 2} (x^2 + 3x - 1)$

=> $\lim_{x \to 2} f(x) = (2)^2 + 3(2) - 1$
=> Ans: $\lim_{x \to 2} f(x) = 4 + 6 - 1 = 9$

7. Ans:(D) doesn't exist.

Given function: $f(x) = -6 + \frac{x}{x^4}$
In this case, even if we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.

Check:
$f(x) = -6 + \frac{x}{x^4} \\ f(x) = -6 + \frac{1}{x^3} \\ f(x) = \frac{-6x^3 + 1}{x^3} \\ Rationalize: \\ f(x) = \frac{-6x^3 + 1}{x^3} * \frac{x^{-3}}{x^{-3}} \\ f(x) = \frac{-6x^{3-3} + x^{-3}}{x^0} \\ f(x) = -6 + \frac{1}{x^3} \\ Same$

If you apply the limit, answer would be infinity.

8. Ans:(A) Doesn't Exist.

Given function: $f(x) = 9 + \frac{x}{x^3}$
Same as Question 7
If we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.

9, 10.
Please attach the graphs. I shall amend the answer. :)

11. Ans:(A) Doesn't exist.

First We need to find out: $\lim_{x \to 9} f(x)$ where,
$f(x) = \left \{ {{x+9, ~~~~~x \textless 9} \atop {9- x,~~~~~x \geq 9}} \right.$

If both sides are equal on applying limit then limit does exist.

Let check:
If x $\textless$ 9: answer would be 9+9 = 18
If x $\geq$ 9: answer would be 9-9 = 0

Since both are not equal, as $18 \neq 0$ , hence limit doesn't exist.

12. Ans:(B) Limit doesn't exist.

Find out: $\lim_{x \to 1} f(x)$ where,

$f(x) = \left \{ {{1-x, ~~~~~x \textless 1} \atop {x+7,~~~~~x \textgreater 1} } \right. \\ and \\ f(x) = 8, ~~~~~ x=1$

If all of above three are equal upon applying limit, then limit exists.

When x < 1 -> 1-1 = 0
When x = 1 -> 8
When x > 1 -> 7 + 1 = 8

ALL of the THREE must be equal. As they are not equal. 0 $\neq$ 8; hence, limit doesn't exist.

13. Ans:(D) -∞; x = 9

f(x) = 1/(x-9).

Table:

x f(x)=1/(x-9)

----------------------------------------

8.9 -10

8.99 -100

8.999 -1000

8.9999 -10000

9.0 -∞

Below the graph is attached! As you can see in the graph that at x=9, the curve approaches but NEVER exactly touches the x=9 line. Also the curve is in downward direction when you approach from the left. Hence, -∞, x =9 (correct)

14. Ans: -6

s(t) = -2 - 6t

Inst. velocity = $\frac{ds(t)}{dt}$

Therefore,

$\frac{ds(t)}{dt} = \frac{ds(t)}{dt}(-2-6t) \\ \frac{ds(t)}{dt} = 0 - 6 = -6$

At t=2,

Inst. velocity = -6

15. Ans: +∞, x =7

f(x) = 1/(x-7)^2.

Table:

x f(x)= 1/(x-7)^2

--------------------------

6.9 +100

6.99 +10000

6.999 +1000000

6.9999 +100000000

7.0 +∞

Below the graph is attached! As you can see in the graph that at x=7, the curve approaches but NEVER exactly touches the x=7 line. The curve is in upward direction if approached from left or right. Hence, +∞, x =7 (correct)

-i

7 0

3 years ago

Read 2 more answers

If you know the area of a rectangle can you predict its perimeter? Explain

Anuta_ua [19.1K]

No. The area doesn't tell you the dimensions, and you need
the dimensions if you want the perimeter.

If you know the area, you only know the product of the length and width,
but you don't know what either of them is.

In fact, you can draw an infinite number of different rectangles
that all have the same area but different perimeters.

Here. Look at this.
I tell you that a rectangle's area is 256. What is its perimeter ?

-- If the rectangle is 16 by 16, then its perimeter is 64 .
-- If the rectangle is 8 by 32, then its perimeter is 80 .
-- If the rectangle is 4 by 64, then its perimeter is 136 .
-- If the rectangle is 2 by 128, then its perimeter is 260 .
-- If the rectangle is 1 by 256, then its perimeter is 514 .
-- If the rectangle is 0.01 by 25,600 then its perimeter is 51,200.02

6 0

4 years ago

Read 2 more answers

Listed below is the amount of commissions earned last month for the eight members of the sales staff at Best Electronics. Calcul

Solnce55 [7]

Answer:

0.438

Step-by-step explanation:

Given the data:

980.9, 1036.5, 1099.5, 1153.9, 1409.0, 1456.4, 1718.4, 1721.2

Coefficient of skewness:

3 * (mean - median) / standard deviation

The mean of the dataset :

Σ(X) / N ; N = sample size = 8

980.9+1036.5+1099.5+1153.9+1409.0+1456.4+1718.4+1721.2

= 10575.8 / 8

= 1321.975

Median :

980.9, 1036.5, 1099.5, 1153.9, 1409.0, 1456.4, 1718.4, 1721.2

1/2(n + 1)th term

1/2(9) = 4.5th term

(1153.9+1409.0) / 2

= 1281.45

Standard deviation:

Sqrt[Σ(X - mean)²/ (N - 1)]

Using calculator :

Standard deviation estimate of population = 277.882456

Coefficient of skewness :

3(1321.975 - 1281.45) / 277.882456

121.575 / 277.882456

= 0.4375051

= 0.4375

Using software excel :

Using excel's AVERAGE, MEDIAN and STDEV.P functions, the Coefficient of skewness can be obtained using the formula :

3 * (mean - median) / standard deviation

Coefficient of skewness obtained is 0.438

8 0

2 years ago