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3 years ago

Can someone plz help me

Mathematics

1 answer:

Colt1911 [192]3 years ago

4 0

Answer:

x is less than or equal to negative 14.

Step-by-step explanation:

so for now we should pretend that the greater than or equal to is an equal sign, and simplify the problem to get x alone on a side

remove 5 from each side

-x/3=1/3-5

-x/3=14/3

multiply both sides by 3

-x=14

x=-14

so we can now replace the equal sign with the equal or greater to, so x is less than or equal to -14

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the sum of the measure of the interior angle of a convex polygon is 1080 find the number of sides of each polygon

pogonyaev

Answer:

Step-by-step explanation:

The formula to calculate the sum of interior angles of polygon is (n - 2)180

Where n represents number of sides

(n-2)180 = 1080 ------ Divide through by 180

(n-2)180/180 = 1080/180

n-2 = 6

n = 6+2

n = 8

6 0

3 years ago

Please show me step by step on how to solve this.

Readme [11.4K]

Well, you have to be given an interval. That is not an interval.

You should be given something like $1 \leq x \leq 2$

If you add those fractions up you'll just get a point on the number line.

Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3

You'll end up with a point on 2/3

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3 years ago

In a competition between players X and Y, the first player to win three games in a row or a total of four games wins. How many w

OLEGan [10]

Answer:

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

<h3>¹Case - 1: Y wins the fourth game:</h3>

The competition ends with Y winning as he/she won 3 games in a row

<h3>Case - 2: X wins the fourth game:</h3>

more games are required to decide the winner

<h3>Sub-case - a: X wins the fifth game:</h3>

more games are required to decide the winner

<h3>²Sub-sub-case - i: X wins the sixth game:</h3>

The competition ends with X winning as he/she won 3 games in a row

<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

The competition ends with Y winning as he/she won 4 games in total

<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴<u>The competition can be played in 7 different ways</u>

7 0

3 years ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

3 years ago

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What is the mean of 20, 37, 43, 54, 83, 102, 117, 160, 208?

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Answer is 91.56 You add all the numbers up and divide by 9(There are 9 numbers in the sequence).

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