Answer:
The missing value is(0,0)
Step-by-step explanation:
The complete question is:
2x+3y=5x-y
Complete the missing value in the solution to the equation.
( ,0)
<u>Solution:</u>
We have given:
2x + 3y = 5x - y
Combine the like terms:
2x-5x= -y-3y
-3x = -4y
Both negative signs will be cancelled out by each other.
So we have,
3x = 4y
We have given y = 0
Then
3x = 4*0
3x= 0
Divide both sides by 3
3x/3 = 0/3
x = 0
y=0
Therefore missing value is(0,0)
35 3/4= 35.75 and 1/8=0.125
35.75/0.125= 286
Answer:
{2, 6}
Step-by-step explanation:
w/2w-3=4/w is ambiguous. Did you mean
w 4
---------- = ------ ? If so, please enclose "2w - 3" inside parentheses.
2w - 3 w
Cross multiplying, we get w² = 8w - 12.
Putting this into standard form, we get:
w² - 8w + 12 = 0, which factors into (w - 2)(w - 6) = 0.
The solutions are found by setting each factor = 0 separately and solving the resulting equations for w: {2, 6}.
Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.
