Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
Step-by-step explanation:
c
Answer: Infinite solutions
Step 1: Turn this into y=Mx+b form
The current equation is—
-2x+5y=30
Since we want to get y alone on the left side, let’s add 2x on both sides
-2x+5y=30
+2x +2x
____________
5y=2x+30
Step 2: Again, trying to get y alone, we need to divide 5 on both sides
5y=2x+30
/5 /5 /5
________
y=2/5x+6
Step 3: Now that we know how to find y, substitute that in where y is in the equation
-2x + 5(2/5x+6) = 30
-2x + 2x + 30 = 30
30=30
Seeing that you cannot get a specific answer for y when solving, there is an infinite number of solutions
Hope this is right and it helps comment below for more questions :)
Answer:
The way I was taught to do it is to change value into a total fraction, then multiple the numerators together, multiply the denominators together, and finally reduce as far as possible.
7/9 x 5 2/5 = 7/9 x 27/5 = 189/45 = 4 9/45 = 4 1/5
1 3/4 x 4 1/6 = 7/4 x 25/6 = 175/24 = 7 7/24
Answer:
70
Step-by-step explanation:
So I assumed that the x was multiplication...so...15x3=45 and 33x5=165...so the perimeter is 210, so you divide that by 3 and the answer is 70!
