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3 years ago

There are 87.4 calories in one serving of cherries. How many calories are in 3.85 servings? Enter your answer in the bo

Mathematics

2 answers:

shtirl [24]3 years ago

8 0

Answer:

336.49

Step-by-step explanation:

Maru [420]3 years ago

7 0

Answer:

336.49

Step-by-step explanation:

Multiply 87.4 times 3.85 to find your answer.

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Step-by-step explanation:

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3 years ago

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After Lynda's initial client assessment, she has noted that her client will require inventory management to avoid out-of-stock s

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2 years ago

Stu trained for a triathlon for 5 hours yesterday. He ran 5 miles and then biked 80 miles. His biking speed is 15 mph faster tha

lara31 [8.8K]

Answer:

Step-by-step explanation:

Given as :

The distance cover while running = $D_1$ = 5 miles

Let The speed for running = $S_1$

The distance cover with bike = $D_2$ = 80 miles

The speed for biking = $S_2$ = 15 mph + $S_1$

Total Time taken = 5 hours

Now Time = $\dfrac{\textrm Distance}{\textrm Speed}$

∴ 5 hour = $\frac{D_1}{S_1}$ + $\frac{D_2}{S_2}$

Or, 5 hour = $\frac{5}{S_1}$ + $\frac{80}{15+S_1}$

Or, 5 hour = $\frac{75 + 5 S_1 + 80 S_1}{S_1(15+S_1)}$

or, 5 × ( $S_1^{2}+15 S_1$ ) = $85 S_1 + 75$

Or, $5 S_1^{2} + 75 S_1$ - $85 S_1 - 75$ = 0

or, $5 S_1^{2} -10 S_1 - 75$ = 0

or, $S_1^{2} -2 S_1 - 15$ = 0

Or, $S_1^{2} -3 S_1 + 5 S_1- 15$ = 0

Or, $S_1 (S_1 - 3) + 5 (S_1 - 3)$ = 0

Or, $(S_1 - 3) ( S_1 + 5 )$ = 0

∴ $S_1$ = 3 , - 5

So, the running speed = 3 mile per hour

And the biking speed = 15 mph + 3 mph = 18 mile per hour

Hence The running speed of Stu is 3 mile per hour . Answer

7 0

3 years ago

PLS HELP!! Jason bought glass vases for his booth at the fair. If he bought 13 vases and the total weight was 34.97 lb, how much

Stels [109]

Answer:

D. 2.69 lb is your answer

13vases=34.97lb

1 vase=34.97/13=2.69lb

6 0

3 years ago

Quizizz 10 pts each help please WITH PIC brainiest guaranteed

lawyer [7]

Answer:

2. $-2m^4-6m^2+4m+9$

3. $-2m^4-6m^2-4m+9$

Step-by-step explanation:

In general we can write a polynomial in standard form as

$ax^n+bx^n^-^1+cx^n^-^2+...+px+q$

Given $4m-2m^4-6m^2-4m+9$

Combine the like terms: 4m and -4m

4m-4m=0

We have 4m-4m=0

So, write the remaining terms

$-2m^4-6m^2+9+0$

= $-2m^4-6m^2+9$

This is in decreasing order of powers.

Hence the answer is the standard form is

$-2m^3-6m^2+9$

But in the given options, you can choose option 2 and option 3 are in standard form.

Because they are in decreasing order of powers.

In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.

-2m^4-6m^2+4m+9

-2m^4-6m^2-4m+9

I hope this helps you.

And please comment if I need to do corrections.

Please let me know if you have any questions.

8 0

3 years ago