We want to create a linear equation to model the given situation.
A) c(r) = $6.00 + $1.50*r
B) 19 rides.
We know that the carnival charges $6.00 for entry plus $1.50 for each ride.
A) With the given information we can see that if you ride for r rides, then the cost equation will be:
c(r) = $6.00 + $1.50*r
Where c(r) is the cost for going to the carnival and doing r rides.
B) If you have $35.00, then we can solve:
c(r) = $35.00 = $6.00 + $1.50*r
Now we can solve the equation for r.
$35.00 = $6.00 + $1.50*r
$35.00 - $6.00 = $1.50*r
$29.00 = $1.50*r
$29.00/$1.50 = r = 19.33
Rounding to the next whole number we get: r = 19
This means that with $35.00, Dennis could go to 19 rides.
If you want to learn more, you can read:
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Answer:
Step-by-step explanation:
a.10^4=10000
b.10×9×8×7=5040
Let x = months
so we know that price of software package is $20
Now we need to find x the price of one month
we know that Angie and Kenny spent 115 total
Angie: 20 + 3x ( one software pack + 3(price of one month)
Kenny: 20+ 2x ( one software pack + 2( price of one month)
So Angie + Kenny = $ 115
20 + 3y + 20 + 2y = 115
combine like terms and solve for x. That will give you the cost of one month
40 + 5x = 115
-40 -40
5x= 75
5x/5 = 75/5
x=15
Answer:
Cost of shrubs = 23
Cost of tree = 47
Step-by-step explanation:
Let
Cost of shrubs = x
Cost of tree = y
13x + 4y = 487 (1)
6x + 2y = 232 (2)
Multiply (2) by 2
12x + 4y = 464 (3)
13x + 4y = 487 (1)
Subtract (3) from (1)
13x - 12x = 487 - 464
x = 23
Substitute x = 23 into (2)
6x + 2y = 232 (2)
6(23) + 2y = 232
138 + 2y = 232
2y = 232 - 138
2y = 94
y = 94/2
= 47
y = 47
Answer:
we have to find the quotient and the remainder when (x³ + 5x + 3x² + 5x³ + 3) is divided by (x² + 4x + 2) ♥9 dividend = x² + 4x + 2 using Euclid division lemma, x² + 4x + 2) x² + 5x³ + 3x² + 5x + 3(x³ - 4x² + 19x - 65 x² + 4x² + 2x³ - 4x² + 3x² + 3x² - 4x*-16x³8x² 19x³ + 11x² + 5x 19x³ +76x² + 38x -65x²-33x + 3 -65x²-260x - 130 +227x + 133 Therefore the quotient is x² - 4x + 19x - 65 and remainder is 227x + 133
