6) A cylindrical shaped silo has a diameter of 18 feet and a height of 4 feet. How much water can the silo hold, in terms of π?
2 answers:
The amount of water silo can hold in terms of π is 324π cubic feet
<h3><u>Solution:</u></h3>Given that cylindrical shaped silo has a diameter of 18 feet and a height of 4 feet
To find: Amount of water silo can hold in terms of π
This means we are asked to find the volume of cylindrical shaped silo
<em><u>The volume of cylinder is given as:</u></em>
Where "r" is the radius of cylinder
"h" is the height of cylinder
π is the constant has a value 3.14
Given diameter = 18 feet
Substituting the values in formula, we get
Thus amount of water silo can hold in terms of π is 324π cubic feet
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Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
The correct option is;
∠A ≅ ∠X
Step-by-step explanation:
The given coordinates of the points of triangle ACB are;
A(-4, 4), C(-1, 3), B(-4, 0)
The given coordinates of the points of triangle XYZ are;
X(0, 8), Y(8, 8), Z(6, 2), therefore, we have
The length. l. of segment is given by the following formula;
For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)
For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4
For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2
For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8
For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2
For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10
Therefore;
XY ~ AB, XZ ~ BC, ZY ~ AC
Which gives;
∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z
