Answer:
x = 3 + √6 ; x = 3 - √6 ; 
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:
for the equation ax² + bx + c = 0
thus,
the roots are
or
or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are
or
or
and, x = 
or
and, x = 
or
and, x = 
or
and,
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ; ;
Answer:
7:yes
8:no
9:yes
10:sorry
Step-by-step explanation:
Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.
Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.
1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13
2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
Answer: 9
Step-by-step explanation:
To solve this problem, we need to use our order of operations, or PEMDAS.
Parenthesis
Exponent
Multiply
Divide
Add
Subtract
6÷2(1+2) [parenthesis]
6÷2(3) [multiply/divide from left to right]
3(3) [multiply]
9
Now, we know that the answer is 9.
