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solniwko [45]
3 years ago
6

Write an expression to represent three minus the product of two and a number x

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

<em>3 minus ___</em> ⇒ 3 - ___

<em>the product of 2 and a number x</em> ⇒ 2x

"3 minus the product of 2 and a number x" ⇒ 3 - 2x

_____

Each part of the description has a translation.

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If the circumference of a circle measures 12π cm, what is the area of the circle in terms of π?
frez [133]
So the formula for the circumference of a circle is π x diameter
Since we know the the circumference already, we just divide that by π:

12π / π = 12

Now we halve the diameter to get the radius:
12 / 2 = 6 

The area of a circle is π x radius²
So the area is:

·π x 6² = 36π·  (or 113 not in terms of π) 
5 0
3 years ago
May you please help me with Highschool Ap Calculus.​
nadya68 [22]

Answer:

dy/dx = x=-1

Step-by-step explanation:

by use of intergration to get the values of yaxis and x axis,,the values are -2, -4,

5 0
3 years ago
Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y
Pepsi [2]

Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

c=28

Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

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3 years ago
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NISA [10]

Answer:

Mario ate 27.27% of her cookies

8 0
3 years ago
The two triangles illustrated below are similar. What are the values of x and y?
poizon [28]

Answer:

{ \bf{by \: relations : }} \\ { \tt{ \frac{28}{7}  =  \frac{x}{8} }} \\  \\ { \tt{x =  \frac{28 \times 8}{7} }} \\ x = 32 \\  \\ { \tt{y = 83 \degree}}

5 0
3 years ago
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