42,42,24,36,60,6
1st Find the mean X̅
=(42+42+24+36+60+6)/6 = 35
2nd find the difference between the data set value and the mean (x - X̅)
and square them:
(42-35)² = 49
(42-35)² = 49
(24-35)² = 121
(36-35)² = 1
(60-35)² = 625
(6-35)² = 814
Now add up te result ∑(x-X̅)² =1659
Answer:
The correct answer is 5 years i.e. 2008.
Step-by-step explanation:
Price of the automobile in 2003 is $32000.
Depreciation per year is given by $1740.
Therefore let the car value is depreciated for t number of years.
Value depreciated for t years is given by $ (1740t).
The final value of the car after t years is given to be $23300.
Thus the equation is given by 32000 - 1740t = 23300.
⇒ 1740t = 32000 - 23300
⇒ 1740t = 8700
⇒ t = 5
Thus after 5 years the value of the car is $23300.
Thus in 2008 the depreciated price of the car would be $23300.
P = 10% = 0.1
q = 1 - 0.1 = 0.9
P(at least one defective calculator) = P(1) + P(2) + P(3) + P(4) = 1 - P(0)
The brobability of a binomial distribution is given by
where: n = 4
Therefore,
P(at least one defective calculator) = 1 - 0.6561 = 0.3439
Answer for 13: 89 percent because 89/100 is .89 or 89 percent
Answer for 14: part a: 1/10 because Each person gets ten percent so 10 times 10 is 100
Part b: it can be expressed as 0.10 in decimal form
Expected number of wins=number of plays times the probability of winning
w=20(14.5/100)
w=20(0.145)
w=2.9
w≈3
So you would expect to win 3 times out of 20 attempts (rounded to the nearest whole number of wins)
