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Elanso [62]
3 years ago
5

A mathematical phrase represented by numbers, variables, and operations is a(n)

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

Expression

Step-by-step explanation:

Expressions use numbers, variables, and operations to form a mathematical calculation.

Equations are similar except they use equal signs, so that makes them different than expressions.

If this answer is correct, please make me Brainliest!

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3)
Wewaii [24]

Answer:

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

Step-by-step explanation:

Given -

\frac{1}{3} volume of sand in bucket is able to cover \frac{1}{9} area of the entire playground

Thus,

For covering  \frac{1}{9} unit area of the entire playground, the amount of sand required is equal to  \frac{1}{3}  of the total volume of sand in bucket

For covering  1 unit area of the entire playground, the amount of sand required is equal to

\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3}  * \frac{9}{1} \\\frac{9}{3}\\= 3

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

4 0
3 years ago
Is it possible to make a triangle with measure of 3mm 9mm and 5mm​
tatyana61 [14]

Answer: No

Step-by-step explanation: if you mean the measure of a is 3, the measure of b is 9 and the measure of c is 5, c being the hypotenuse then the answer is no because the the sides of a and b must be less than the measure of c. If 5 wasn’t the hypotenuse then the answer would be different.

(KEEP IN MIND THAT IF 9 IS THE HYPOTENUSE THEN THE ANSWER IS YES)

Hope this helps! :)

4 0
2 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
2 years ago
Use your shapes to create a new shape with an area of 1 square unit that is not a square. Trace your shape.
Elena-2011 [213]

A new shape with an area of 1 square unit that is not a square can be formed by combining two small triangles

<h3>How to determine the new shape?</h3>

The given parameters are:

  • Area of square = 1 square unit
  • Large triangles = 2
  • Medium triangles = 1
  • Small triangles = 4

The area of each small triangle is:

Area = 0.5 square unit

Multiply both sides by 2

2 * Area of triangle = 1 square unit

Substitute Area of square = 1 square unit

2 * Area of triangle = Area of square

This means that a new shape can be formed by combining two small triangles

Read more about area at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
Please help me with this last problem
sdas [7]
The answer to question #5 is 17
4 0
3 years ago
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