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kap26 [50]
3 years ago
14

A triangle has side lengths 3 cm, 4 cm, and 5 cm. What is the area in square centimeters?

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0
5^2=3^2+4^2 ⇒ the triangle has an ungle =90 °

The area is 3*4/2=6 cm^2
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Two angles are supplementary. The measure of one angle is 4 more than 7 times the other angle. Find the measures of both angles.
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Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

Step-by-step explanation:

Smaller angle = x

Larger angle = 3x + 4

Therefore, we have:

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3 years ago
What is the length of side AD?. . . 6 cm. 8.5 cm. 10.4 cm. 12 cm
ludmilkaskok [199]
In triangle ABC, AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x)  tan30 <span>=(24−x)/</span><span>√3
</span>

In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
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AD = AC - DC = 24- (24-x) = 6</span></span>
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3 years ago
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Find the length of side BY for the given triangle.
saul85 [17]

Answer:

option 3- 5 square root 2

Step-by-step explanation:

\sin 45° = \frac{BY}{OY} \\  \\  \frac{1}{ \sqrt{2} }  =  \frac{BY}{10}  \\  \\ BY =  \frac{10}{ \sqrt{2} }  \\  \\ BY =  \frac{10 \times  \sqrt{2} }{ \sqrt{2} \times  \sqrt{2}  }   \\  \\ BY =  \frac{10 \sqrt{2} }{2 }   \\  \\  \huge \red{ \boxed{BY =  5 \sqrt{2} }}

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