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kap26 [50]
3 years ago
14

A triangle has side lengths 3 cm, 4 cm, and 5 cm. What is the area in square centimeters?

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0
5^2=3^2+4^2 ⇒ the triangle has an ungle =90 °

The area is 3*4/2=6 cm^2
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Simplify 5x + 2(x - 3) = -2(x - 1)
Kruka [31]

Answer:

x=8/9

Step-by-step explanation:

5x+2(x-3)=-2(x-1)

1) Distribute 2 to x and -3:

5x+2x-6=-2(x-1)

2) Distribute -2 to x and -1:

5x+2x-6=-2x+2

3) Combine alike terms:

7x-6=-2x+2

4) Add 2x to both sides:

9x-6=2

5) Add 6 to both sides:

9x=8

6) Divide both sides by 9:

x=8/9

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Step-by-step explanation:

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2 years ago
What will it cost to carpet a rectangular floor measuring 9 feet by 21 feet if the carpet costs $30.82 per square yard?
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6 0
3 years ago
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3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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