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3 years ago

I will give u a five dollar gift card plz help!!!

Mathematics

2 answers:

juin [17]3 years ago

6 0

Answer:

1. The measure of ∠WOV is 60°. You would use complementary angles that are adjacent (∠WOV, and ∠XOW)

2. The measure of ∠YOZ is 60°. You would use the vertical angles that are non-adjacent (∠WOV, and ∠YOZ). These two angles are congruent so they would have the same measure. These angles combined also create supplementary angles

3. Another way to find the measure of ∠YOZ would be to make/write an equation and solve for x. For example, (3x+30)°=60°. x would equal 10 because 10x3=30+30=60°

Step-by-step explanation:

1. Since a complementary angle would equal 90°, simply subtract 30° from 90° resulting in 60°.

2. Because vertical angles are congruent and (∠WOV, and ∠YOZ) are a pair of them, they equal the same as each other so they're both 60°.

3. You can make any equation with x included as long as it equals 60° mine was just an example you can make your own like 10x+10=60 or 4x+20=60. Also to create your equation you also need to use the angle fact of the vertical angles

NikAS [45]3 years ago

6 0

Answer:

1. The measure of ∠WOV is 60°. You would use complementary angles that are adjacent (∠WOV, and ∠XOW)

3. Another way to find the measure of ∠YOZ would be to make/write an equation and solve for x. For example, (3x+30)°=60°. x would equal 10 because 10x3=30+30=60°

Step-by-step explanation:

1. Since a complementary angle would equal 90°, simply subtract 30° from 90° resulting in 60°.

2. Because vertical angles are congruent and (∠WOV, and ∠YOZ) are a pair of them, they equal the same as each other so they're both 60°.

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PLEASE HELP 100 POINTS!!!!!!

horrorfan [7]

Answer:

A) See attached for graph.

B) (-3, 0) (0, 0) (18, 0)

C) (-3, 0) ∪ [3, 18)

Step-by-step explanation:

Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.

Given piecewise function:

$g(x)=\begin{cases}x^3-9x \quad \quad \quad \quad \quad \textsf{if }x < 3\\-\log_4(x-2)+2 \quad \textsf{if }x\geq 3\end{cases}$

Therefore, the function has two definitions:

$g(x)=x^3-9x \quad \textsf{when x is less than 3}$

$g(x)=-\log_4(x-2)+2 \quad \textsf{when x is more than or equal to 3}$

When <u>graphing</u> piecewise functions:

Use an open circle where the value of x is <u>not included</u> in the interval.
Use a closed circle where the value of x is <u>included</u> in the interval.
Use an arrow to show that the function <u>continues indefinitely</u>.

<u>First piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

$\implies g(3)=(3)^3-9(3)=0 \implies (3,0)$

Place an open circle at point (3, 0).

Graph the cubic curve, adding an arrow at the other endpoint to show it continues indefinitely as x → -∞.

<u>Second piece of function</u>

Substitute the endpoint of the interval into the corresponding function:

$\implies g(3)=-\log_4(3-2)+2=2 \implies (3,2)$

Place an closed circle at point (3, 2).

Graph the curve, adding an arrow at the other endpoint to show it continues indefinitely as x → ∞.

See attached for graph.

The x-intercepts are where the curve crosses the x-axis, so when y = 0.

Set the <u>first piece</u> of the function to zero and solve for x:

$\begin{aligned}g(x) & = 0\\\implies x^3-9x & = 0\\x(x^2-9) & = 0\\\\\implies x^2-9 & = 0 \quad \quad \quad \implies x=0\\x^2 & = 9\\\ x & = \pm 3\end{aligned}$

Therefore, as x < 3, the x-intercepts are (-3, 0) and (0, 0) for the first piece.

Set the <u>second piece</u> to zero and solve for x:

$\begin{aligned}\implies g(x) & =0\\-\log_4(x-2)+2 & =0\\\log_4(x-2) & =2\end{aligned}$

$\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b$

$\begin{aligned}\implies 4^2&=x-2\\x & = 16+2\\x & = 18 \end{aligned}$

Therefore, the x-intercept for the second piece is (18, 0).

So the x-intercepts for the piecewise function are (-3, 0), (0, 0) and (18, 0).

From the graph from part A, and the calculated x-intercepts from part B, the function g(x) is positive between the intervals -3 < x < 0 and 3 ≤ x < 18.

Interval notation: (-3, 0) ∪ [3, 18)

Learn more about piecewise functions here:

brainly.com/question/11562909

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2 years ago

[100 POINTS] What is the measure of the arc from A to B that does not pass through C?

prohojiy [21]

Answer:

the answer to the questions is 140

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Lina20 [59]

Answer:

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Step-by-step explanation:

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June 1st = 1223 starting balance

Dima020 [189]

<u>Answer:</u>

The average daily balance for the month of June is 55.16

Solution:

Given, June 1st = 1223 starting balance

June 10th = 615 deposit

So these will add in the account

June 15th = withdrawal of -63

June 22nd = withdrawal of -120

These will be subtracted from the account.

$\therefore$ We have to add the deposits and subtract the withdrawals from the starting balance to obtain the total amount.

So, the total amount deposited in June is (1223 +615-63-120) = 1655

The total days in June is 30. In 30 days, the total deposit is 1655. To calculate the average balance, we have to divide the total amount by the total number of days in the month.

So, in 1 day the deposit is $\frac{1655}{30} = 55.16$

Hence, the average daily balance for June is = 55.16

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3 years ago

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Alja [10]

Answer:

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Step-by-step explanation:

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