Answer:
The values of x and y are x = 6 and y = 9
Step-by-step explanation:
MNOP is a parallelogram its diagonal MO and PN intersected at point A
In any parallelogram diagonals:
- Bisect each other
- Meet each other at their mid-point
In parallelogram MNOP
∵ MO and NP are its diagonal
∵ MO intersect NP at point A
- Point A is the mid-point pf them
∴ MO and NP bisect each other
∴ MA = AO
∴ PA = AN
∵ MA = x + 5
∵ AO = y + 2
- Equate them
∴ x + 5 = y + 2 ⇒ (1)
∵ PA = 3x
∵ AN = 2y
- Equate them
∴ 2y = 3x
- Divide both sides by 2
∴ y = 1.5x ⇒ (2)
Now we have a system of equations to solve it
Substitute y in equation (1) by equation (2)
∴ x + 5 = 1.5x + 2
- Subtract 1.5x from both sides
∴ - 0.5x + 5 = 2
- Subtract 5 from both sides
∴ - 0.5x = -3
- Divide both sides by - 0.5
∴ x = 6
- Substitute the value of x in equation (2) to find y
∵ y = 1.5(6)
∴ y = 9
The values of x and y are x = 6 and y = 9
Answer:
It is (-3-(-6)+5)^4=4096
Step-by-step explanation:
B
if it is not correct sory
Answer:
1c

1d

Step-by-step explanation:
From the question we are told that
The probability of telesales representative making a sale on a customer call is 
The mean is 
Generally the distribution of sales call made by a telesales representative follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the mean is mathematically represented as

=> 
=> 
Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

=> 
=> ![P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20%5B%20%5E%7Bn%7DC_0%20%2A%20%20%280.15%20%29%5E0%20%2A%20%20%281-%200.15%29%5E%7Bn-0%7D%5D%20%3E%200.95)
=> ![1 - [1 * 1* (0.85)^{n}] > 0.95](https://tex.z-dn.net/?f=%201%20-%20%5B1%20%20%2A%20%201%2A%20%20%280.85%29%5E%7Bn%7D%5D%20%3E%200.95)
=> ![[(0.85)^{n}] > 0.05](https://tex.z-dn.net/?f=%20%20%5B%280.85%29%5E%7Bn%7D%5D%20%3E%200.05)
taking natural log of both sides

=> 