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Bogdan [553]
3 years ago
8

What is y=2 plus 4?​

Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer:

y=6

Step-by-step explanation:

all you do is add 4 and 2

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What is 2 1/2 + 4 2/5 in simplest form
Marysya12 [62]

Answer:6 9/10

Step-by-step explanation:

4 0
3 years ago
Simplify the expression by combining like terms. -8y + 2 + 10y - 7<br> Please help
Alecsey [184]

Answer:

<u>2y - 5 (read below)</u>

Step-by-step explanation:

-8y + 10y = 2y

2 + (-7) = -5

Your expression could/would be:

2y - 5.

Hope this helps!

8 0
3 years ago
Read 2 more answers
We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab
777dan777 [17]

Answer:

(a) The distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

(c) The value of P(\bar X>0.50) is 0.50.

Step-by-step explanation:

It is provided that random variables X_{i} are independent and identically distributed Bernoulli random variables with <em>p</em> = 0.50.

The random sample selected is of size, <em>n</em> = 100.

(a)

Theorem:

Let X_{1},\ X_{2},\ X_{3},...\ X_{n} be independent Bernoulli random variables, each with parameter <em>p</em>, then the sum of of thee random variables, X=X_{1}+X_{2}+X_{3}...+X_{n} is a Binomial random variable with parameter <em>n</em> and <em>p</em>.

Thus, the distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

The sample size is large, i.e. <em>n</em> = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=p=0.50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05

(c)

Compute the value of P(\bar X>0.50) as follows:

P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\

                    =P(Z>0)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the value of P(\bar X>0.50) is 0.50.

8 0
3 years ago
Write a number sentence to represent the sum modeled on the number line. In two or more complete sentences, explain your reasoni
Afina-wow [57]

Answer:

0 + (-2.5) + 5

Step-by-step explanation:

from 0 to -2.5 then to 5 so add 0 + (-2.5) + 5

4 0
3 years ago
Multiply: -z^3(5 + z - 4z^2)
Alex787 [66]
- 5z^3 - z^4 + 4z^5 is the answer.
7 0
3 years ago
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