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Bogdan [553]
3 years ago
8

What is y=2 plus 4?​

Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer:

y=6

Step-by-step explanation:

all you do is add 4 and 2

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Find the distance between the points (-8, -3) and (-2, 5). Hint: Use the Pythagorean theorem. ​
Drupady [299]

Answer:

1/5

Step-by-step explanation:

Use Pythagoras theorem

5 0
2 years ago
ITS AN EDUCATIONAL EMERGENCY!!! This is due tonight how do I solve this?? PLEASE HELPP
kvasek [131]

Answer:

Mabel used 12 dimes and 7 quarters to pay for her granola bar.

Step-by-step explanation:

A dime= 10 A quarter= 25

12×10=120

7×25=175

175+120=295

12-7=5

4 0
2 years ago
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Answer: ok LOL thx XD

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8 0
2 years ago
2x=8 <br>so find the value of x​
melisa1 [442]

Answer:

x = 4

Step-by-step explanation:

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x =4

6 0
2 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
3 years ago
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