Answer:
Im sorry but don't cheat.
Step-by-step explanation:
Answer:
m∠MON = 15°
Step-by-step explanation:
The given parameters are;
m∠LON = 77°
m∠LOM = 9·x + 44°
m∠MON = 6·x + 3°
By angle addition postulate, we have;
m∠LON = m∠LOM + m∠MON
Therefore, by substituting the known values, we have;
∴ 77° = 9·x + 44° + 6·x + 3°
77° = 9·x + 44° + 6·x + 3° = 15·x + 47°
77° = 15·x + 47°
77° - 47° = 15·x
15·x = 77° - 47° = 30°
15·x = 30°
x = 30°/15 = 2°
x = 2°
Given that m∠MON = 6·x + 3° and x = 2°, we have;
m∠MON = 6 × 2° + 3° = 12° + 3° = 15°
m∠MON = 15°.
Either 1/10 or 10%
Hope this helps!!!
Step-by-step explanation:
has critical points where the derivative is 0:
The second derivative is
and 
, which indicates a local minimum at 
with a value of 
.
At the endpoints of [-2, 2], we have 
and 
, so that has an absolute minimum of 
and an absolute maximum of 
on [-2, 2].
So we have
