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jonny [76]
3 years ago
9

Is 21 a multiple of 6

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0
No, 21 is a multiple of 7
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Select all the parallelograms that have an area of 16 square units
Georgia [21]

Answer:it's c and b

Step-by-step explanation:

It's c an b

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3 years ago
What are the first nonzero multiples of 3
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How Do You Factor 5xy - 10x
Ira Lisetskai [31]
5xy-10x

5x are both common, so take that as a factor:

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Under a dilation of scale factor 2 centered at (3,1), Pentagon IRONS becomes Pentagon
geniusboy [140]

Answer:

(a+k(x-a), b+k(y-b))

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Step-by-step explanation:

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3 years ago
For each expression listed, is it a difference of squares? Explain yes or no and why or why not. Explain in enough detail so the
Harlamova29_29 [7]
<h2>Explanation:</h2><h2></h2>

If we can write a polynomial in the form a^2-b^2, then we can factor it as:

a^2-b^2=(a-b)(a+b)

In this problem, we have the following expressions:

1. \ y^5 - 25 \\ \\  2. \ 9m^2n^2-121  \\ \\ 3. p^{18} - q^{10} \\ \\ 4. 16r^2 - 27

  • For 1 and 4 we can't write this in the form a^2-b^2 so this is not a difference of squares.

  • For 2:

9m^2n^2-121 =3^2m^2n^2-11^2 \\ \\ =(3mn)^2-11^2 =(3mn-11)(3mn+11)

So we could write 2 as a difference of squares.

  • For 3:

p^{18} - q^{10}=(p^9)^2-(q^5)^2=(p^9-q^5)(p^9+q^5) \\ \\ \\ Remember: \ (a^m)^n=a^{mn}

So we could write 2 as a difference of squares.

7 0
3 years ago
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