Answer:
authentication
Explanation:
At the authentication process, there is a way of identifying a user, this is typically done by having the user enter a valid user name and valid password before access is granted. Here at authentication the process is based on each user having a unique set of criteria for gaining access.
The AAA server have to ascertain by comparing a user's authentication credentials with other user credentials stored in a database. In the event the credentials match, the user is granted access to the network. But on the other hand, If the credentials varies, and authentication fails then network access will be denied.
1.) Go get bag of pet food from cabinet
2.) Set the bag on counter
3.) Get pet food dish out of cabinet
4.) Open pet food bag, pour pet food into dish
5.) Close bag, give dish to pet.
num = int(input("Enter a number: "))
i = 2
while num > 1:
if num % i == 0:
num = num / i
print(i, end=" ")
i = 2
i += 1
I hope this helps!
Human centered technology often recommends best practices to computer designers and manufacturers, ...............
Human-Computer Interaction is a study that particularly focuses more on the design of computer technology and the interaction between humans and computers. Since the 1980s when HCI surfaced, it has become a crucial tool in popularizing the idea that the interaction between a user and a computer should resemble a human-to-human, open-ended dialogue. When HCI is done well, a human-centered approach powers the creation of products that resonates more deeply with a certain audience. This will ultimately drive engagement and growth.
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
