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4 years ago

Solve the formula for the area of a parallelogram the height,

Mathematics

1 answer:

valkas [14]4 years ago

5 0

Answer:

h=A/b

Step-by-step explanation:

Think of putting number in the place of the letter, for example

A is 4

b is 2

h is 2

4=2 x 2 then plug the numbers in the right spot

2=4/2 then see what can be rearranged or what is left to make the

equation true

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The three sides of an equilateral triangle measure (x + 12), (2x - 5) and (3x - 22) inches. The sides of the triangle measure

agasfer [191]

All 3 sides are equal in an equilateral triangle...

2x - 5 = 3x - 22
-5 + 22 = 3x - 2x
17 = x

2x - 5 = 2(17) - 5 = 34 - 5 = 29
3x - 22 = 3(17) - 22 = 51 - 22 = 29
x + 12 = 17 + 12 = 29

as u can see, all sides measure 29 inches

8 0

3 years ago

Read 2 more answers

The price of a CD decreased from $15 to $10. What is the percent of decrease

insens350 [35]

Answer:

Step-by-step explanation:

amount of decrease is $15 - $10 = $5

as a percentage of the original price

100($5/$15) = 33⅓ %

8 0

2 years ago

ALGEBRA Find the value of x in each figure. HELP ASAP I WILL MARK BRAINLIEST

Nadya [2.5K]

Answer:

x=104°

Step-by-step explanation:

180=(x+4) +72

180-72=x+4

108=x+4

108-4=x

104=x

x=104°

Hope this helps! :)

4 0

3 years ago

On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl

worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.

8 0

3 years ago

Precalculus please help

JulijaS [17]

Answer:

amplitude = 2

period = 4

midline = y = -1

equation = either $2sin(\frac{pi}{2}x+\frac{pi}{2} )-1$ or $2sin(\frac{pi}{2}(x+1) )-1$ depending on what format you're using

Step-by-step explanation:

the amplitude is the distance from the bottommost point to the topmost point

so if we use the points (0,1) and (2,-3), the min y value is -3 and the max y value is 1

so amplitude = ymax - ymin = 1 - - 3 = 4

amplitude = 4

the period is the distance it takes to complete one cycle

we have (0,1) and (4,1) which are two crest points

the distance between these is x2 - x1 = 4 - 0 = 4

period = 4

the midline is a horizontal line bisecting the sin line, which would be in the middle of its min and max y values

we already found that ymax = 1 and ymin = -3

so the midline would be y = (ymax + ymin) / 2 = (1 -3) /2 = -1

midline = y = -1

to find the sin equation, we will fill out the equation

asin(b(x-d))+c

a is the amplitude = 2

b = 2π/period = 2π/4 = π/2

c is the vertical shift. the midline of sine is originally at y = 0

since it is at y = -1 here, the vertical shift is -1 - 0 = -1

d is the horizontal shift. the middle of the upwards portion of the sine graph is originally at x = 0, but in the picture we see that it is at x = -1 so the shift is -1 - 0 = -1

a = 2, b = π/2, c = -1, d = -1

plug these values into the equation to get

asin(b(x-d))+c

2sin(π/2(x--1))+-1

=2sin(π/2(x+1))-1

=2sin(πx/2+π/2)-1

equation = either $2sin(\frac{pi}{2}x+\frac{pi}{2} )-1$ or $2sin(\frac{pi}{2}(x+1) )-1$ depending on what format you're using

4 0

3 years ago