Solve the following system of equations graphically on the set of axes below.
1 answer:
The solution of the given equations is: (-1.5, 1.5)
Step-by-step explanation:
Linear equation usually represents a straight line. When a system of two liner equations is given, the point of intersection of lines represented by both equations is the solution of the system of equations.
We will plot the lines of both equations and find their point of intersection (Picture Attached)
We can see in the picture that two lines intersect at (-1.5, 1.5)
Hence,
The solution of the given equations is: (-1.5, 1.5)
Keywords: Linear equations, variables
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Since you haven't provided the graph, I'll explain each one and you choose the one suiting your given.
<u>The parent modulus function is:</u>
g(x) = |x|
It is centered at the origin and opens upwards.
A coefficient inside the modulus |x+k| means that the function is shifted along the x-axis
If "k" is <u>positive</u>, the shift will be to the <u>left</u>. If "k" is <u>negative</u>, the shift will be to the <u>right</u>.
A coefficient outside the modulus |x| + h means that the function is shifted along the y-axis
If "h" is <u>positive</u>, the shift will be <u>upwards</u>. If "h" is <u>negative,</u> the shift will be <u>downwards</u>.
<u>Now, let's check each of the options:</u>
<u>g(x) = |x+4| - 2 :</u>
This function is shifted 4 units to the left and 2 units down. It will be centered at (-4,-2). Check the blue graph in the attachment.
<u>g(x) = |x-4| - 2 :</u>
This function is shifted 4 units to the right and 2 units down. It will be centered at (4,-2). Check the black graph in the attachment.
<u>g(x) = |x-2| - 4 :</u>
This function is shifted 2 units to the right and 4 units down. It will be centered at (2,-4). Check the red graph in the attachment.
<u>g(x) = |x-2| + 4 :</u>
This function is shifted 2 units to the right and 4 units up. It will be centered at (2,4). Check the green graph in the attachment.
All 4 graphs are shown in the attached picture.
Hope this helps :)
