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elena55 [62]
3 years ago
6

What is 43.586 rounded to the nearest tenth

Mathematics
2 answers:
miskamm [114]3 years ago
8 0
<span>43.586 rounded to the nearest tenth is 43.60 because the number in the tenth place is 5 but the number to right of it is greater than 5.</span>
gayaneshka [121]3 years ago
5 0
It want's the .0 decimal place so.

43.6 remember when the number behind it is greater than or equal to 5 you round up.
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Answer:

expanded it would be 0.05 x 50 + 0.05 x 40

Step-by-step explanation:

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3 years ago
Which number line represents all of the values of x for the equation x2 = 49?
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Hello,

x²=49
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The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
lubasha [3.4K]

Answer:

a. 10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. 0.2457 = 24.57% probability 10 of the problems can be resolved today

c. 0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today

d. 0.5017 = 50.17% probability more than 10 of the problems can be resolved today

Step-by-step explanation:

For each case, there are only two possible outcomes. Either they are solved, or they are not. Cases are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

It can resolve customer problems the same day they are reported in 80% of the cases.

This means that p = 0.8

Sample of 13 cases:

This means that n = 13

a. How many of the problems would you expect to be resolved today? What is the standard deviation?

Expected:

E(X) = np = 13*0.8 = 10.4

Standard deviation:

\sqrt{V(X)} = \sqrt{13*0.8*0.2} = 1.44

10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. What is the probability 10 of the problems can be resolved today?

This is P(X = 10). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457

0.2457 = 24.57% probability 10 of the problems can be resolved today.

c. What is the probability 10 or 11 of the problems can be resolved today?

This is p = P(X = 10) + P(X = 11). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457

P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680

p = P(X = 10) + P(X = 11) = 0.2457 + 0.2680 = 0.5137

0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today.

d. What is the probability more than 10 of the problems can be resolved today?

This is

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680

P(X = 12) = C_{13,12}.(0.8)^{12}.(0.2)^{1} = 0.1787

P(X = 13) = C_{13,13}.(0.8)^{13}.(0.2)^{0} = 0.0550

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) = 0.2680 + 0.1787 + 0.0550 = 0.5017

0.5017 = 50.17% probability more than 10 of the problems can be resolved today

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Answer: David has 11 DVDs and 27 books.

Step-by-step explanation:

When numbers are put in ratio form they are meant to compare their relative sizes.

The first number will be the first item being compared to the other.

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In the same vein, a ratio of books to DVDs of 27:11 means that David has 27 books and 11 DVDs.

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Answer:

Hello! answer: 9

Step-by-step explanation:

3 × 3 = 9

3² = 9

4 0
3 years ago
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