<span> a) F' = 6 sin(x^2) = 0
x^2 = pi
x = sqrt(pi)
b) Fmax = F(1) + integral [1, pi] f(x) dx = 9.7743 </span>
Answer:
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
Please give brainliest