Question

The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

Answer 1

Answer:

20/3 ft or 6 2/3 ft

Step-by-step explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W

$L = \dfrac{A}{W}$

$L = \dfrac{56~\frac{2}{3}~sq~ft}{8~\frac{1}{2}~ft}$

Change the mixed numbers into fractions.

$a\frac{b}{c} = \dfrac{ac + b}{c}$

$L = \dfrac{\frac{56 \times 3 + 2}{3}}{\frac{8 \times 2 + 1}{2}}$

$L = \dfrac{\frac{170}{3}}{\frac{17}{2}}$

$L = \dfrac{170}{3} \div \dfrac{17}{2}$

$L = \dfrac{170}{3} \times \dfrac{2}{17}$

$L = \dfrac{170 \times 2}{3 \times 17}$

$L = \dfrac{17 \times 10 \times 2}{3 \times 17}$

$L = \dfrac{10 \times 2}{3}$

$L = \dfrac{20}{3}$

Answer: 20/3 ft or 6 2/3 ft