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2 years ago

How many fewer people attended the pacers games than atteneded the clippers game

2 answers:

6 0

Do you have numbers for each game. If so subtract the bigger number from higher then your answer is there.

say you have 189 people at the pacer game and 123 at the clippers you take 189-123=66
so 66 fewer people attened

diamong [38]2 years ago

5 0

so 66 fewer people attened

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Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

2 years ago

3. I think of a number. I subtract 10 and add 5. I then double it. My

ella [17]

Answer:

Step-by-step explanation:

You can divide 50 by 2 which is 25

Then subtract 5

Add 10

And you get your number

It is really simple really ☺️

5 0

2 years ago

Find the indicated sum for each sequence. S9 of –9, 36, –144, 576, ...

gogolik [260]

This is a geometric sequence with a common ratio of -4:

-9*-4=36

36*-4=-144

-144*-4=576

Thus, the 9th term would be equal to:

(-4)^5*576 which is -589824

The exponent 5 comes from the fact that 4 terms have already been displayed and we need 9-4 more terms to get to the 9th term. Since we are multiplying by -4 only, the 5 remains an exponent

5 0

3 years ago

Which of the following is a rational number?

bezimeni [28]

Answer:

-19

Step-by-step explanation:

It is a non repeating decimal

3 0

1 year ago

Read 2 more answers

Can someone please help me solve for x? i already have y