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Gennadij [26K]
3 years ago
6

PLZZZ HELP WILL GIVE BRAINLEST only if correct

Mathematics
1 answer:
Fittoniya [83]3 years ago
5 0

Part a

power = 3.9 \times  {10}^{33} erg \:  {sec}^{ - 1}  

energy \: in \: 3.25 \times  {10}^{3} sec = 3.9 \times  {10}^{33}  \times 3.25 \times  {10}^{3}  = 12.675 \times  {10}^{36}  

part b  

1.435 . 10^3 mm = 1.4m

1.435 . 10^-3 mm = 0.001435m  

so the first one ie 1.4m is more reasonable as tge second one is too small quantity.

Hope it helps.

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Answer:

\frac{10}{15}-\frac{2}{5}=\frac{4}{15}

Step-by-step explanation:

We know that

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Let us consider two different fractions with different denominators

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Lets subtract the two fractions

\frac{10}{15}-\frac{2}{5}\:\:\:\:

\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}

=\frac{2}{3}-\frac{2}{5}

\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5

\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}

\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3

\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}

so

=\frac{10}{15}-\frac{6}{15}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{10-6}{15}

\mathrm{Subtract\:the\:numbers:}\:10-6=4

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Therefore,

\frac{10}{15}-\frac{2}{5}=\frac{4}{15}

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Answer:

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