The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.
Answer:
(2, 1 )
Step-by-step explanation:
Given the 2 equations
y = 6x - 11 → (1)
- 2x - 3y = - 7 → (2)
Substitute y = 6x - 11 into (2)
- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side
- 2x - 18x + 33 = - 7
- 20x + 33 = - 7 ( subtract 33 from both sides )
- 20x = - 40 ( divide both sides by - 20 )
x = 2
Substitute x = 2 into (1) for corresponding value of y
y = 6(2) - 11 = 12 - 11 = 1
Solution is (2, 1 )
Answer:
9) x=58
10) r=4
11) m=4
12) p=3
13) x=6
14) x=-3
15) s=400
Step-by-step explanation:
9) x+2/5=12
x5 x5
x+2=60
-2 -2
x=58
10) 7r + 14 - 3r =30
-14 -14
<u>7r-3r</u>=16
4r=16
÷4 ÷4
r=4
11) 
m+2=6
-2 -2
m=4
÷ ÷
m=4
12) <u>2</u>(5p+9)=48
10p+18=48
-18 -18
10p=30
÷10 ÷10
p=3
13) <u>5</u>(2x-8)=20
10x-40=20
+40 +40
10x=60
÷10 ÷10
x=6
14)<u>6</u>(3-2x)=54
18-12x=54
-18 -18
-12x=36
÷-12 ÷-12
x=-3
15) 
-
=40
x5 x5
2s-=200
x2 x2
<u>2s-1s</u>=400
1s=400
÷1 ÷1
s=400
Best Answer:<span> </span><span>So first we need both areas, then we can relate them, and then divide the circle by the square:
A(circle) = πr^2
A(square) = L*W or (2r)*(2r) which is (2r)^2
For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square.
Ratio: (πr^2)/(4r^2) = π/4</span>
Answer:what goes around comes around
Step-by-step explanation:
"i need points too thanks"
