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3 years ago

10

Can someone help me with this?

1 answer:

Arte-miy333 [17]3 years ago

7 0

Answer:

(x-2)(x-2)

Step-by-step explanation:

You should be trying to find two numbers that add to make the coefficient of x (in this case, -4), and two numbers that multiply to make the constant term (in this case, +4). The two numbers that work for both of those criteria are -2 and -2.

-2 x -2 = +4 (satisfies the constant term)

-2 + -2 = -4 (satisfies the coefficient of x)

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Solve for the value of r. (8r+6)° (9r-7)

lukranit [14]

Answer:

r = 13

Step-by-step explanation:

these angles are vertical and are congruent

8r + 6 = 9r - 7

6 = r - 7

13 = r

8 0

2 years ago

How do you solve 7n-2=6n-2n

pantera1 [17]

First combine like terms:
6n-2n = 4n
7n-2=4n
subtract 7n from both sides
7n-2=4n
-7n -7n
-2=-3n
divide -2 on both sides.
n=1.5

7 0

3 years ago

Which of the points does NOT satisfy the inequality shaded in the diagram?

strojnjashka [21]

The answer i got was A (4,0)

5 0

3 years ago

A taxi driver determines the fare using the formula F=1.50+2.6m, where F is the total fare and m id the numbet a miles driven. W

Lady bird [3.3K]

Just do 1.50 + 2.6(3.5)

The answer is $10.60

3 0

3 years ago

The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me

julia-pushkina [17]

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 200 mg

Sample mean, $\bar{x}$ = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis for a two tailed test

$H_{0}: \mu = 200\\H_A: \mu \neq 200$

We use Two-tailed t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799$

c) Now,

$t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930$

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

4 0

3 years ago