Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:

Compute the degrees of freedom as follows:


Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:


*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer: The r<span>-value for the linear function related to the ordered pairs is very close to zero, so it is not a good representation of the data. A quadratic model would better represent the data because there is a turning point within the data set. The data increases then decreases, which is what the graph of a quadratic does. </span>
Answer:
No.
Step-by-step explanation:
Price of each pretzel = $3.25
Price of each drink = $1.85
Price of each bag of popcorn = $0.99
Maximum money to be spent = $10
Price of two pretzels = $3.25
2 = $6.5
Price of two drink = $1.85
2 = $3.70
Price of two bags of popcorn = $0.99
2 = $1.98
Total money spent for buying two items of each type = $6.5 + $3.70 + $1.98 = $12.18
The money spent when 2 pretzels, 2 drinks and 2 bags of popcorn are bought is $12.18.
But maximum money available is $10.
Therefore, Clare would not be able to buy 2 pretzels, 2 drinks and 2 bags of popcorn with the amount of money available.
Answer: Zero and Any real number
Step-by-step explanation:
Point Q could be represented by any real numbers. And zero if it's located at the origin. The same is applicable to value at point P. It's just that at P, the value can't be equal to Zero.