Answer: A, because it is a 30, 60, 90 triangle. To get the 34 they had to times the number by 2 so you divide that by 2 and it gives you 17 then you have the square root of 3* 17, that doesn’t mathematically work so it stays as 17*the square root of 3
Answer:
I would say that by the 20th figure, there would be more than 400 small triangles by the 20th figure.
Step-by-step explanation:
Based on figure 1 and 2, I'm guessing the ratio is 2.
Figure 4: 32
Figure 5: 64
Figure 6: 128
Figure 7: 256
Figure 8: 512
Figure 9: 1,024
X+y=23
X-y=7.4
X+y=23
y=23-X
X-y=7.4
(23-y)-y=7.4
23-2y=7.4
-2y=-15.6
Y=7.8
X+y=23
X+7.8=23
X=15.2
Therefore the two numbers are 7.8 & 15.2
Answer:
![P(A\textrm{ and }B)=\frac{3}{14}](https://tex.z-dn.net/?f=P%28A%5Ctextrm%7B%20and%20%7DB%29%3D%5Cfrac%7B3%7D%7B14%7D)
Step-by-step explanation:
Given:
![P(A)=\frac{4}{7}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cfrac%7B4%7D%7B7%7D)
![P(B|A)=\frac{3}{8}](https://tex.z-dn.net/?f=P%28B%7CA%29%3D%5Cfrac%7B3%7D%7B8%7D)
We know that, conditional probability of B given that A has occurred is given as:
. Expressing this in terms of
, we get
![P(A\cap B)=P(B|A)\times P(A)](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28B%7CA%29%5Ctimes%20P%28A%29)
Plug in the known values and solve for
. This gives,
![P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28B%7CA%29%5Ctimes%20P%28A%29%5C%5CP%28A%5Ccap%20B%29%3D%5Cfrac%7B3%7D%7B8%7D%5Ctimes%20%5Cfrac%7B4%7D%7B7%7D%5C%5CP%28A%5Ccap%20B%29%3D%5Cfrac%7B12%7D%7B56%7D%3D%5Cfrac%7B3%7D%7B14%7D)
Therefore, the probability of events A and B occurring is
.