Thanks for the points oh and idk
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
112 <span>≥ b+128
First: You would subtract 128 on both sides of your sign
You would get: -16</span><span>≥ b <That is your answer
HOPE THIS HELPS! ^_^</span>
27.5 and 22.5 are the two numbers
Answer:
The exponent will be 4*10^11
Step-by-step explanation:
^11 This means 11 is an exponent on top.
Hope it helps. Let me know.
