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Dennis_Churaev [7]
3 years ago
14

Which sequence is modeled by the graph below? Points: (2,8) (3,4) (4,2) (5,1)

Mathematics
1 answer:
asambeis [7]3 years ago
7 0

Answer:

a_n=16 \cdot (\frac{1}{2})^{n-1}

Step-by-step explanation:

This sequence is geometric because while x is going up by 1, the y sequence has a common ratio.

That is, term/previous equals same number per consecutive y terms.

So 1/2=2/4=4/8 is the common ratio.

The first term is when x=1. We can find this y by figuring out what we can multiply to our common ratio, 1/2, to get the next term,8.

Since 8(2)=16, then the first term is 16.

In general,

y=a_1 \cdot (r)^{x-1}

Or if preferred:

a_n=a_1 \cdot (r)^{n-1}

where a_1 is first term and r is common ratio.

Plug in information:

a_n=16 \cdot (\frac{1}{2})^{n-1}

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Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = 10x^5 + 8x^4 - 15x^3 +2x^2 - 2
vagabundo [1.1K]

Given:

The function is:

f(x)=10x^5+8x^4-15x^3+2x^2-2

To find:

All the possible rational zeros for the given function by using the Rational Zero Theorem.

Solution:

According to the rational root theorem, all the rational roots are of the form \dfrac{p}{q},q\neq 0, where p is a factor of constant term and q is a factor of leading coefficient.

We have,

f(x)=10x^5+8x^4-15x^3+2x^2-2

Here,

Constant term = -2

Leading coefficient = 10

Factors of -2 are ±1, ±2.

Factors of 10 are ±1, ±2, ±5, ±10.

Using the rational root theorem, all the possible rational roots are:

x=\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}.

Therefore, all the possible rational roots of the given function are \pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}.

5 0
3 years ago
A person drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 200 times. Here are the observed f
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Answer:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

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Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the frequencies

H1: There is a difference in the frequencies

The level of significance assumed for this case is \alpha=0.01

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The observed values are:

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And the expected values are for this case the same E_i = \frac{200}{6}= 33.33

And now we can calculate the statistic:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

p_v = P(\chi^2_{5} >6.7)=0.244

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

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