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3 years ago

Hbdh What is u+ka= ba for a

1 answer:

8 0

Minus ka from both sides
u=ba-ka
undistribute a
u=(a)(b-k)
diivde both sides by (b-k)
$\frac{u}{b-k} =x$
$x= \frac{u}{b-k}$

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Y+3 1/2=6 help pleaseee

Verdich [7]

3 1/2 = 7/2
so y+7/2 = 6
y=6-7/2 = 12-7 / 2 = 5/2 = 2 1/2

8 0

3 years ago

Savings account A has 1500 and pays 3.5% interest yearly. Savings account B has 1400 and pays 4% interest yearly. the savings ac

Alex73 [517]

To find these numbers, we do this:
Savings Acc A:
1.35(1500) = 2025
Savings Acc B:
1.04(1400) = 1456
Savings Account A has earned the most interest.

7 0

3 years ago

Read 2 more answers

The centroid cuts each median into two segments. The shorter segment is _ _ _ _ the length of the entire segment.

adoni [48]

Answer:

Step-by-step explanation:

One third

3 0

2 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago

15 kg 30 gm divided by 5= how much gm?

alekssr [168]

90gm because you times 15 by 30 and then you divide

7 0

3 years ago