Answer:
The correct answer is iron-transport proteins
Explanation:
Siderophores are proteins produced by bacteria, and compete with the host's iron-transport proteins. They aim to bind and "hijack" the host's cell iron molecules for their own pathogenic cell processes
The right answer is C.
Classically positive interactions or facilitators between species are divided into two broad categories:
- those where the two partners involved benefit from each other: the mutualisms (symbolized by + / +)
- those where one of the two partners makes a profit or an advantage while the other gets nothing from it without being affected negatively: it is the commensalism symbolized by + / 0.
It may be that bacterial commensalism has an interest in its host (the animal) in the sense that it protects against parasites, or on the contrary, it favors their appearance.
Samoset and Squanto both speak using the English language.
Answer:
0 additive alleles = A0B0C0D0
1 additive allele = A+B0C0D0, A0B+C0D0, A0B0C+D0, A0B0C0D+
2 additive alleles = A+B0C0D+, A+BC+D0, A0B+C+D0, A0B+C0D+, A0B0C+D+, A+B+C0D0
3 additive alleles = A+B+C+D0, A+B+C0D+, A+B0C+D+, A0B+C+D+
4 additive alleles = A+B+C+D+
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
