Question

Which equation represents the hyperbola in general form?

Answer 1

ANSWER

D.

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

EXPLANATION

The standard equation of the hyperbola is

$\frac{ {(y - 2)}^{2} }{4} - \frac{ {(x - 2)}^{2} }{9} = 1$

We multiply through by 36 to obtain:

$9 {(y - 2)}^{2} - 4( {x - 2)}^{2} = 36$

We now expand to get,

$9( {y}^{2} - 4y + 4) - 4( {x}^{2} - 4x + 4) = 36$

Expand :

$9 {y}^{2} - 36y + 36 - 4 {x}^{2} + 16x - 16 = 36$

To get the general form, we equate everything to zero to get,

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

The correct choice is D.