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jenyasd209 [6]
3 years ago
15

Why do crumple zones reduce the force in a collision.

Physics
1 answer:
Stels [109]3 years ago
4 0
Crumple zones are areas of a vehicle that are designed to crush in a controlled way in the collision
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4. Protons and neutrons are held together to form this _________
Olenka [21]

Answer:

strong nuclear force.

Explanation:

hope this helps you!!

8 0
2 years ago
Which of the following is most likely to be attracted to a magnet?
Naya [18.7K]

Answer:

c

Explanation:

because it is made out of metel

7 0
3 years ago
A man pushes a box along a flat, frictionless surface using a force of 500 N. The box was moved a distance of 2.5 m. The actual
andrey2020 [161]

Answer:

Workdone = 1250Nm

Explanation:

<u>Given the following data;</u>

Force, F = 500N

Distance, d = 2.5m

Workdone is given by the formula;

Workdone = force * distance

Substituting into the equation, we have

Workdone = 500 * 2.5  

Workdone = 1250Nm

Therefore, the actual work done by the worker is 1250 Newton-meter.

4 0
3 years ago
A car is moving with a uniform velocity.find out the force of which it is moving
olya-2409 [2.1K]
If a car is moving with uniform velocity, then there is
no net force acting on it.

The force of the engine is exactly enough to balance
the forces of friction and air resistance against the car.

Also notice that there can't be any centripetal force, and the
car can't be on a curve.  If it's moving with "uniform velocity",
that means steady speed in a straight line.
7 0
4 years ago
You break a piece of Styro foam packing material, and it releases lots of little spheres whose electric charge makes them stick
stich3 [128]

Answer:

The magnitude of charge on each sphere is q=2.50\times 10^{-8}\ C.

Explanation:

Given that,

Force of repulsion between the charges, F = 22 mN

The distance between spheres, r = 16 mm = 0.016 m

It is mentioned that both the spheres carry equal charges. The force between charges is given by :

F=\dfrac{kq^2}{r^2}

q=\sqrt{\dfrac{Fr^2}{k}}

q=\sqrt{\dfrac{22\times 10^{-3}\times (0.016)^2}{9\times 10^9}}

q=2.50\times 10^{-8}\ C

So, the magnitude of charge on each sphere is q=2.50\times 10^{-8}\ C. Hence, this is the required solution.

3 0
3 years ago
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