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algol [13]
3 years ago
13

A man pushes a box along a flat, frictionless surface using a force of 500 N. The box was moved a distance of 2.5 m. The actual

work done by the worker was _____
Physics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

Workdone = 1250Nm

Explanation:

<u>Given the following data;</u>

Force, F = 500N

Distance, d = 2.5m

Workdone is given by the formula;

Workdone = force * distance

Substituting into the equation, we have

Workdone = 500 * 2.5  

Workdone = 1250Nm

Therefore, the actual work done by the worker is 1250 Newton-meter.

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A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refrac
elena55 [62]

Answer:

A

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5 0
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Joe and Max shake hands and say goodbye. Joe walks east 0.50 km to a coffee shop, and Max flags a cab and rides north 3.45 km to
timama [110]

Answer:

3.486 km

Explanation:

Suppose Joe and Max's directions are perfectly perpendicular (east vs north). We can calculate their distance at the destinations using Pythagorean theorem:

s = \sqrt{J^2 + M^2}

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