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Aleksandr [31]
3 years ago
11

You break a piece of Styro foam packing material, and it releases lots of little spheres whose electric charge makes them stick

annoyingly to you. If two of the spheres carry equal charges and repel with a force of 22 { mN} when they're 16 { mm} apart, what's the magnitude of the charge on each?
Physics
1 answer:
stich3 [128]3 years ago
3 0

Answer:

The magnitude of charge on each sphere is q=2.50\times 10^{-8}\ C.

Explanation:

Given that,

Force of repulsion between the charges, F = 22 mN

The distance between spheres, r = 16 mm = 0.016 m

It is mentioned that both the spheres carry equal charges. The force between charges is given by :

F=\dfrac{kq^2}{r^2}

q=\sqrt{\dfrac{Fr^2}{k}}

q=\sqrt{\dfrac{22\times 10^{-3}\times (0.016)^2}{9\times 10^9}}

q=2.50\times 10^{-8}\ C

So, the magnitude of charge on each sphere is q=2.50\times 10^{-8}\ C. Hence, this is the required solution.

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The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?
shusha [124]

Answer:

The pressure increases by a factor 8

Explanation:

For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:

p_1 V_1 = p_2 V_2

where

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p_2 is the final pressure

V_1 is the initial volume

V_2 is the final volume

For the gas in this problem, the volume is reduced from

V_1 = 4 L

to

V_2 = 0.5 L

so we can rewrite the equation as

\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8

this means that the pressure of the gas will increase by a factor 8.

5 0
4 years ago
What is the rms current flowing through a light bulb that uses an average power of 30.0 W when it is plugged into a wall recepta
Amiraneli [1.4K]

Answer:

0.125 A

Explanation:

From the question given above, the following data were obtained:

Power (P) = 30 W

rms voltage (Vrms) = 240 V

rms Current (Irms) =?

The power in an electric circuit is given by the following equation:

Power (P) = current (I) × voltage (V)

With the above formula, we can obtain the rms current flowing through the bulb as shown below:

Power (P) = 30 W

rms voltage (Vrms) = 240 V

rms Current (Irms) =?

P = Irms × Vrms

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Divide both side by 240

Irms = 30 / 240

Irms = 0.125 A

Thus, the rms current flowing through the light bulb is 0.125 A

7 0
3 years ago
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