I'll do a similar problem, and I challenge you to do this on your own using similar methods!
x+5y+2z=23
8x+4y+3z=12
9x-3y-7z=-10
Multiplying the first equation by -8 and adding it to the second one (to get rid of the x) and also multiplying the first equation by -9 and adding the third one to get rid of the x there too, we end up with
-36y-13z=-92
and
-48y-25z=-217
Multiplying both equations by -1, we get
36y+13z=-92
48y+25z=217
Multiplying the (new) first equation by -4/3 and adding it to the second (to get rid of the y), we get
(7+2/3)z=94+1/3
Dividing both sides by (7+2/3) to separate the z, we get
z=

Plugging that into
48y+25z=217, we can subtract 25z from both sides and divide by 48 to get

Lastly, we plug this into x+5y+2z=23 to get
x=23-5y-2z by subtracting 5y+2z from both sides to get
Good luck, and feel free to ask with any questions!
Gotta move that b to the side ya dig
0, 1/2, -53, and 0.433 all belong in rational category
Answer:
100
Step-by-step explanation:
Answer:
y = (√3)/2
Step-by-step explanation:
The unit circle has equation ...
x^2 +y^2 = 1
For x = 1/2, the value of y can be found to be ...
(1/2)^2 +y^2 = 1
y^2 = 1 - 1/4 = 3/4 . . . . . subtract 1/4
y = √(3/4) . . . . . . . . . . take the square root (y > 0 here)
y = (√3)/2