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3 years ago

Plzzzzzzzzzzzzzaaaaaaaaaaaa

Mathematics

1 answer:

pashok25 [27]3 years ago

4 0

Answer:

Step-by-step explanation:

use the quadratic formula and you should end up with this

d=1/32 (33+ $\sqrt{1217}$ )=2.121

The domain is [0,2.121...].

x = -b / 2a = -3.3/(-3.2) = 1.031

max=1.902

so its A

pls mark me brainliest

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Using the figures below, what is the perimeter of the 5th rectangle in the pattern?

maksim [4K]

Each side is increasing their length by 1 every time, and the length is always 1 greater than the height. That means the 5th rectangle will have a height of 5 and a length of 6, which would give it a perimiter of 22.

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3 years ago

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X = -60i + 80 What is the real part of Z? What is the imaginary part of Z?

Deffense [45]

Answer:

the real part is 80

the imaginary part is -60

Step-by-step explanation:

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4 years ago

a falling object travels a distance given by the formula d=5t + 16t^2 ft, where t is measured in seconds. how long will it take

Butoxors [25]

Its given that

$d=5t+16t^{2}$

We need to find t when d = 74

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$16t^{2}+5t-74 = 0$

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t(16t + 37) - 2(16t + 37) = 0

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Therefore, t = 2

Hence, it will take 2 seconds for the object to travel 74 feet.

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3 years ago

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Julia planet a rectangle garden that is 20 feet long she plays 56 feet of fencing around her Garten what is the width of her Gar

Aleksandr-060686 [28]

The width of rectangular garden(b) = 8 feet and

The area of rectangular garden = 160 square feet

Step-by-step explanation:

Given,

The length of rectangular garden(l) = 20 feet and

The perimeter of rectangular garden(fencing) = 56 feet

To find, the width of rectangular garden(b) = ? and

The area of rectangular garden = ?

We know that,

The area of rectangular garden = 2(l + b)

⇒ 2(20 + b) = 56

⇒ 20 + b = 28

⇒ b = 28 - 20 = 8 feet

The width of rectangular garden(b) = 8 feet

∴ The area of rectangular garden = l × b

= 20 feet × 8 feet

= 160 square feet

Hence, the width of rectangular garden(b) = 8 feet and

the area of rectangular garden = 160 square feet

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3 years ago

Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

Applying the law of sines in the right triangle BDC

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

Applying the law of sines in the right triangle ABC

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$

Find the value of BC

$BC=(sin(70\°))\frac{6.6}{sin(20\°)}$

$BC=18.12\ m$

therefore

The height of the tree is 18.12 m

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