Ask question

Ask question

All categories

3 years ago

8

A cylinder has the height of 5 m and a diameter that is four times the measure of the height using 3.14 for pie which of the fol

lowing can be used to calculate the volume

1 answer:

worty [1.4K]3 years ago

3 0

Answer: you can type this into a cylinder calculator online and get your answer

Step-by-step explanation:

You might be interested in

Work out: 496 g + 6 kg 76 g – 2 kg 846 g

aliina [53]

Answer:

3 Kg 726g

Step-by-step explanation:

Kg g

0 496

<u> 6 076</u> +

6 572 -

<u>2 846</u>

3 726

5 0

3 years ago

Read 2 more answers

What’s the answer? Because am having a hard time with this math problem.

Studentka2010 [4]

9514 1404 393

Answer:

34.5 square meters

Step-by-step explanation:

We assume you want to find the area of the shaded region. (The actual question is not visible here.)

The area of the triangle (including the rectangle) is given by the formula ...

A = 1/2bh

The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...

A = (1/2)(11 m)(9 m) = 49.5 m^2

The rectangle area is the product of its length and width:

A = LW

The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...

A = (5 m)(3 m) = 15 m^2

The shaded area is the difference between the triangle area and the rectangle area:

shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2

The shaded region has an area of 34.5 square meters.

7 0

3 years ago

When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio

dmitriy555 [2]

Answer:

$\dfrac{xy}{pm}=8$

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

x = k(pm)/y . . . . where k is the constant of proportionality

__

This can be solved for k:

k = xy/pm

For the given values, the value of k is ...

k = (2)(4)/((0.5)(2)) = 8

Then the relation between the variables can be written ...

(xy)/(pm) = 8

5 0

2 years ago

Consider three events A, B and C with following properties.

lisov135 [29]

By the inclusion/exclusion principle,

$\mathbb P(D)=\mathbb P(A\cup B\cup C)$
$\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)$
$\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}$
$\mathbb P(D)=\dfrac{16}{39}\neq1$

So the union of A, B, and C does not constitute the entire sample space.

5 0

3 years ago

What are the first and last deciles of the standard Normal distribution?

aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0

3 years ago