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lions [1.4K]
3 years ago
9

If I have something like -x^2 when I plug the number in, will it be positive or negative and why

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0
The order of operations tells you exponentiation is done before multiplication or addition. That is, the value of x is squared before the sign is applied.

Your result will be negative for any non-zero value of x.
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ser-zykov [4K]

Answer:

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5 0
3 years ago
Use the drawing tool(s) to form the correct answer on the provided graph.
NikAS [45]

Answer:

Here's one way to do it

Step-by-step explanation:

1. Solve the inequality for y

5x - y > -3

-y > -5x - 3

y < 5x + 3

2. Plot a few points for the "y =" line

I chose

\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}

x

−2

−1

0

1

2

y

−7

−2

3

8

13

You should get a graph like Fig 1.

3. Draw a straight line through the points

Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.

See Fig. 2.

4. Test a point to see if it satisfies the inequality

I like to use the origin,(0,0), for easy calculating.

y < 5x + 3

0 < 0 + 3

0 < 3. TRUE.

The condition is TRUE.

Shade the side of the line that contains the point (the bottom side).

And you're done (See Fig. 3).

6 0
3 years ago
Heyyy please help FACTORISE (x-x)​
ratelena [41]

Answer:

The answer is death :/

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The answer is 0

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8 0
3 years ago
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
How i can write that numbers in letters/ como los escriboo en letras
Klio2033 [76]
Six hundred ninty three thousand, five thousand six hundred ninty nine

Three hundred fourty thousand two thousand and eighty nine

I’m confused on the comma for the last 2?
7 0
2 years ago
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