Answer:
I. A' = (5,-5), B' = (-1,6), C' = (6,1)
II. A' = (5,-11), B' = (-1,0), C' = (6,-5)
III. A' = (-5,-2), B = (6,4), C' = (1,-3)
Step-by-step explanation:
We are given the vertices of ΔABC as A = (2,-5), B = (-4,6) and C = (3,1).
I. It is required to 'reflect the triangle about the line x= 3'.
This rule changes (x,y) to (x+3,y).
So, the new vertices are given by,
A' = (2+3,-5) = (5,-5)
B' = (-4+3,6) = (-1,6)
C' = (3+3,1) = (6,1)
II. It is required to 'translate the triangle 3 units to the right and 6 units down'.
This rule changes (x,y) to (x+3,y-6).
So, the new vertices are given by,
A' = (2+3,-5-6) = (5,-11)
B' = (-4+3,6-6) = (-1,0)
C' = (3+3,1-6) = (6,-5)
III. It is required to 'rotate the triangle by 90° about the origin counter-clockwise'.
This rule changes (x,y) to (y,-x).
So, the new vertices are given by,
A = (2,-5) implies A' = (-5,-2)
B = (-4,6) implies B = (6,4)
C = (3,1) implies C' = (1,-3)
