Answer:
2
Step-by-step explanation:
If we look at the graph this is an increasing graph where y increases with respect to x so in other words we can say that y is directly proportional to x.
![y\ \alpha\ x\\](https://tex.z-dn.net/?f=y%5C%20%5Calpha%5C%20x%5C%5C)
and when we remove the proportionality sign we replace it with an equal to sign and a constant. So it becomes ,
![y = kx\\](https://tex.z-dn.net/?f=y%20%3D%20kx%5C%5C)
now to find the Constant of proportionality which is k we can use any ordered pair(coordinate/point) from the graph,
Lets take ( 2 , 4) where 2 represents the value of x on the x-axis and 4 represents the value of y on the y-axis so now,
![y=kx\\(4)=k(2)\\4=2k\\4/2=k\\k=2\\](https://tex.z-dn.net/?f=y%3Dkx%5C%5C%284%29%3Dk%282%29%5C%5C4%3D2k%5C%5C4%2F2%3Dk%5C%5Ck%3D2%5C%5C)
so the constant of proportionality is 2
Answer:
b
Step-by-step explanation:
∠ BAD = 90° and
∠ DAC + ∠ CAB = ∠ BAD, that is
x + 2x - 30 = 90
3x - 30 = 90 ( add 30 to both sides )
3x = 120 ( divide both sides by 3 )
x = 40 → b
Answer:
-5p-3
Step-by-step explanation:
use the distributive property
Answer:
147+25=172
Step-by-step explanation:
Have a nice day!
Brainliest me pls
Answer with Step-by-step explanation:
We are given that
![b_1=(3,4)](https://tex.z-dn.net/?f=b_1%3D%283%2C4%29)
![b_2=(1,1)](https://tex.z-dn.net/?f=b_2%3D%281%2C1%29)
We have to find the speed of river's current and the direction of current flowing.
![b=b_2-b_1=(1,1)-(3,4)=(-2,-3)](https://tex.z-dn.net/?f=b%3Db_2-b_1%3D%281%2C1%29-%283%2C4%29%3D%28-2%2C-3%29)
Speed of river's current=![\mid b\mid](https://tex.z-dn.net/?f=%5Cmid%20b%5Cmid)
Speed of river's current=![\sqrt{(-2)^2+(-3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-2%29%5E2%2B%28-3%29%5E2%7D)
Speed of river's current=![\sqrt{13} m/s](https://tex.z-dn.net/?f=%5Csqrt%7B13%7D%20m%2Fs)
By using the formula
![\mid r\mid =\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=%5Cmid%20r%5Cmid%20%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
Direction of current flowing,![\theta=tan^{-1}(\frac{y}{x})](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E%7B-1%7D%28%5Cfrac%7By%7D%7Bx%7D%29)
![\theta=tan^{-1}(\frac{-3}{-2})=56.3^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E%7B-1%7D%28%5Cfrac%7B-3%7D%7B-2%7D%29%3D56.3%5E%7B%5Ccirc%7D)
The angle lies in third quadrant therefore
![\theta=180+56.3=236.3^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D180%2B56.3%3D236.3%5E%7B%5Ccirc%7D)