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puteri [66]
3 years ago
5

A full-service salon charges $15.00 for a haircut and $0.45 per hair roller used in a perm. What is the minimum number of hair r

ollers that your
budget will allow if you must spend more than $34.00, but less than $50.00 on the haircut and perm?
Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

43 hair rollers.

Step-by-step explanation:

The cost of the haircut ($15.00) and the hair rollers (0.45*43) would equal $34.35, just passing the minimum amount of $34.00.

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Which expression is equivalent to 63?<br> а<br> 06x3<br> О 6х6х6<br> я<br> 6х6х6х6<br> O3х3х3х3х3х3
Ne4ueva [31]
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3 years ago
The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t
Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.96}{2} = 0.02

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.02 = 0.98, so Z = 2.054.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.054\frac{54}{\sqrt{430}} = 5.35

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

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3 years ago
Please help its very urgent toooooooo .
GenaCL600 [577]

Answer

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Step-by-step explanation:

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3 years ago
99 POINT QUESTION, AND BRAINLIEST!!!
77julia77 [94]
\displaystyle\int_{x=1}^{x=14}\frac{1-\cos4x}{4x-\sin4x}\,\mathrm dx

First, replace y=4x and \mathrm du=4\,\mathrm dx. Then you have

\displaystyle\frac14\int_{y=4}^{y=56}\frac{1-\cos y}{y-\sin y}\,\mathrm dy

If we take z=y-\sin y, then immediately we see a differential in the numerator in the form of \mathrm dz=(1-\cos y)\,\mathrm dy. So the integral becomes

\displaystyle\frac14\int_{z=4-\sin4}^{z=56-\sin56}\frac{\mathrm dz}z

and evaluates to

\dfrac14\ln|z|\bigg|_{z=4-\sin4}^{z=56-\sin56}=\dfrac14\left(\ln|56-\sin56|-\ln|4-\sin4|\right)=\dfrac14\ln\left|\dfrac{56-\sin56}{4-\sin4}\right|

making (A) the correct answer.
4 0
3 years ago
Read 2 more answers
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