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3 years ago

One half divided by two fifths

1 answer:

kramer3 years ago

4 0

1/2 divided by 2/5

In order to get the correct answer you need to flip the second fraction and then multiply it with the first fraction so it will stay like this:

1/2 x 5/2

To find the answer you need to multiply 1 x 5= 5 and 2 x 2=4 which will give you the final answer which is:

5/4 as improper fraction or it can also be 1 1/4 as mixed number, both are correct.

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12.

shtirl [24]

B. if u have wdgenuity it’s B i took the test

3 0

2 years ago

WILL MARK BRAINLIEST! Shelly served the volleyball over the net 17 out of 25 times. What is her percentage of serving the ball o

Tju [1.3M]

Answer

68℅

Explanation

17/25 =

17 ÷ 25 =

0.68 =

0.68 × 100/100 =

0.68 × 100% =

(0.68 × 100)% =

68%;

Hope that this helps you and have a great day :)

8 0

3 years ago

Read 2 more answers

Lexie, a bowler, claims that her bowling score is more than 140 points, on average. Several of her teammates do not believe her,

Crazy boy [7]

Answer:

The test statistic is $t = 3.744$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 140$

The The level of significance is $\alpha = 0.05$

The sample size is n = 18

The null hypothesis is $H_o : \mu = 140$

The alternative hypothesis is $H_a : \mu > 140$

The sample mean is $\= x = 155$

The standard deviation is $\sigma = 17$

Generally the test statistics is mathematically represented as

$t = \frac{\= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }$

substituting values

$t = \frac{ 155 - 140 }{ \frac{ 17 }{ \sqrt{18} } }$

$t = 3.744$

7 0

3 years ago

Which is equivalent to radical 10 ^3/4

egoroff_w [7]

Cuberoot(10)^4 is the answer

3 0

3 years ago

Suppose John opens a savings account with $1,000 that compounds interest daily. The APR at the time John deposits the account is

Fed [463]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad \right.\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.5\%\to \frac{3.5}{100}\to &0.035\\
n=
\begin{array}{llll}
\textit{times it compounds per year}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.035}{365}\right)^{365}-1$

4 0

3 years ago